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ICSE Class 9 Physics Question 2 of 16

Heat and Energy — Question 9

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Question

Question 9

Celsius and Fahrenheit scales are related as :

  1. C5\dfrac{\text{C}}{5} = F - 329\dfrac{\text{F - 32}}{9}

  2. C9\dfrac{\text{C}}{9} = F + 325\dfrac{\text{F + 32}}{5}

  3. 5C = 9F + 32\dfrac{9}{\text{F + 32}}

  4. C5\dfrac{\text{C}}{5} = 9(F + 32)9(\text{F + 32})

Answer

C5\dfrac{\text{C}}{5} = F - 329\dfrac{\text{F - 32}}{9}

Reason — The temperature on Celsius and Fahrenheit scales are realted as : C5\dfrac{\text{C}}{5} = F - 329\dfrac{\text{F - 32}}{9}