ICSE Class 9 Physics Question 2 of 20

Laws of Motion — Question 2

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Question

Question 2

The linear momentum of a ball of mass 50 g is 0.5 kg m s-1. Find it's velocity.

Answer

As we know,

linear momentum (p) = mass (m) x velocity (v)

Given,

p = 0.5 kg m s-1

m = 50 g

Converting g to kg,

1000 g=1 kg50 g=(11000)×5050 g=0.05 kg1000\ \text g = 1\ \text {kg} \\[0.5em] 50\ \text g = (\dfrac{1}{1000}) \times 50 \\[0.5em] \Rightarrow 50\ \text g = 0.05\ \text {kg} \\[0.5em]

Hence, m = 0.05 kg

Substituting the values in the formula above we get,

0.5=0.05×vv=0.50.05v=0.10.01v=10 m s10.5 = 0.05 \times \text v \\[0.5em] \Rightarrow \text v = \dfrac{0.5}{0.05} \\[0.5em] \Rightarrow \text v = \dfrac{0.1}{0.01} \\[0.5em] \Rightarrow \text v = 10\ \text {m s}^{-1}\\[0.5em]

Hence, velocity = 10 m s-1