ICSE Class 9 Physics Question 9 of 20

Laws of Motion — Question 3

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Question

Question 3

Two bodies A and B of same mass are moving with velocities v and 2v respectively.

Compare :

(i) their inertia (ii) their momentum.

Answer

(i) The factor on which inertia of a body depends is mass.

More the mass, more is the inertia of the body. Thus, if mass of two bodies is same their inertia will also be same.

Hence, inertia of A and B will be same as mass of both A and B are same.

Hence, ratio of their inertia is 1 : 1

(ii) As we know, momentum of a body (p) = mass (m) x velocity (v)

Given, mass of A and B are equal.

For A,

PA = mvA

For B,

PB = mvB

Ratio between the two is —

P<em>AP</em>B=mv<em>Amv</em>B\dfrac{{\text P}<em>\text A}{\text {P}</em>\text B} = \dfrac{\text m{\text v}<em>\text A}{\text m{\text v}</em>\text B} \\[0.5em]

As, mass of A = mass of B , hence,

P<em>AP</em>B=v<em>Av</em>B\dfrac{{\text P}<em>\text A}{{\text P}</em>\text B} = \dfrac{{\text v}<em>\text A}{\text {v}</em>\text B} \\[0.5em]

Substituting the values, we get,

P<em>AP</em>B=v2vP<em>AP</em>B=12\dfrac{{\text P}<em>\text A}{{\text P}</em>\text B} = \dfrac{\text v}{2\text v} \\[0.5em] \Rightarrow \dfrac{{\text P}<em>\text A}{\text {P}</em>\text B} = \dfrac{1}{2} \\[0.5em]

Hence, ratio between the momentum of A and B is 1 : 2