The magnification for a mirror is -3. How are u and v related?
Magnification (m) = - image distance (v)object distance (u)\dfrac{\text {image distance (v)}}{\text{object distance (u)}}object distance (u)image distance (v)
Given,
−3=−vu⇒v=3u-3 = -\dfrac{\text{v}}{\text{u}} \\[0.5em] \Rightarrow \text{v} = \text{3u}−3=−uv⇒v=3u
Hence, v = 3u
