Question 12A body weighs 20 gf in air and 18 gf in water. Calculate relative density of the material of the body.

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Bright Tutorials · Accepted Answer

Given,Weight of the solid in air (W1) = 20 gfWeight of the solid in water (W2) = 18 gfRelative density of body=(W1W1−W2)=(2020−18)=(202)=10\text{Relative density of body} = \big(\dfrac{\text W_{1}}{\text W_{1} − \text W_{2}}\big) \[0.5em] = \big(\dfrac{20}{20 - 18}\big) \[0.5em] = \big(\dfrac{20}{2}\big) \[0.5em] = 10Relative density of body=(W1​−W2​W1​​)=(20−1820​)=(220​)=10

Upthrust in Fluids, Archimedes' Principle and Floatation — Question 12

Question 12