Model Question Paper 2
Solutions for Biology, Class 10, ICSE
Section A
20 questionsAnswer:
Hypertonic
Reason — In a hypertonic solution the cell loses its shape and shrinks because its cell sap (having low concentration of solute) loses water due to high concentration of hypertonic solution. It is called as exosmosis.
Answer:
Carbon dioxide
Reason — In the process of photosynthesis, the substance which is reduced is Carbon dioxide as oxygen is removed from it and the carbon is used in the formation of glucose.
Name the following :
(i) The number of deaths per 1000 of population per year.
(ii) The liquid waste material produced by factories.
(iii) The scattered golgi bodies in plant cells.
(iv) The structures which help in the formation of spindle fibres in plant cells during cell division.
(v) The part of inner ear responsible for dynamic balance.
Answer:
(i) Mortality rate
(ii) Effluent
(iii) Dictyosomes
(iv) Microtubules
(v) Semi-circular canals
Arrange and rewrite the terms in each group in the correct order so as to be in a logical sequence beginning with the term that is underlined.
(i) Soil water, Xylem, Pericycle, Root hair
(ii) Xylem vessels, Stoma, Mesophyll, Sub-stomatal space
(iii) Light energy, Thylakoid, Glucose, Splitting of water molecules
(iv) Glomerulus, Collecting duct, Loop of Henle, Distal convoluted tubule
(v) Conjunctiva, Retina, Vitreous humour, Cornea
Answer:
(i) Soil water → Root hair → Pericycle → Xylem
(ii) Xylem vessels → Mesophyll → Sub-stomatal space → Stoma
(iii) Light energy → Thylakoid → Splitting of water molecules → Glucose
(iv) Glomerulus → Loop of Henle → Distal convoluted tubule → Collecting duct
(v) Conjunctiva → Cornea → Vitreous humour → Retina
Match the items given in column I with the most appropriate ones in column II and rewrite the correct matching pairs.
Column I | Column II |
---|---|
(i) Thylakoids | Photorespiration |
(ii) Starch formation | Photo-chemical phase |
(iii) ATP | Photosynthesis |
(iv) Autotrophs | Photolysis of water |
(v) Light reaction | Polymerisation |
Phagocytosis | |
Phosphorylation |
Answer:
Column I | Column II |
---|---|
(i) Thylakoids | Photolysis of water |
(ii) Starch formation | Polymerisation |
(iii) ATP | Phosphorylation |
(iv) Autotrophs | Photosynthesis |
(v) Light reaction | Photo-chemical phase |
Choose the odd one out from the following terms and name the category to which the others belong :
(i) Uterine tubes, Seminiferous tubule, Epididymis, Interstitial cells
(ii) Progesterone, Testosterone, Oestrogen, Prolactin
(iii) Conjunctiva, Cornea, Cochlea, Choroid
(iv) Cell wall, Visking bag, Cellophane paper, Parchment paper
(v) Simple goitre, Myxoedema, Cretinism, Acromegaly
Answer:
(i) Odd one — Uterine tubes
Seminiferous tubule, Epididymis, Interstitial cells — Parts of Testis
(ii) Odd one — Testosterone
Progesterone, Oestrogen, Prolactin — Female hormones
(iii) Odd one — Cochlea
Conjunctiva, Cornea, Choroid — Parts of Eye
(iv) Odd one — Cell wall
Visking bag, Cellophane paper, Parchment paper — Semi-permeable membranes
(v) Odd one — Acromegaly
Simple goitre, Myxoedema, Cretinism — Hypothyroidism
Section B
30 questionsAnswer:
Sympathetic nervous system prepares the body for violent action against abnormal conditions while the parasympathetic nervous system is more concerned with re-establishing normal conditions after the violent act is over.
Answer:
Two significant roles of Hepatic Portal system are:
- Glycogenesis — Excess sugar is converted and stored in the liver in the form of glycogen.
- Detoxification — If any poisonous and harmful material is absorbed through food, they are detoxified in the liver.
Given below is a simplified diagrammatic representation of a defect of the human eye. Study the figure and answer the following questions.

(i) Identify the defect (technical term).
(ii) Mention two reasons for the above defect.
(iii) Draw a neat and labelled diagram for the “correction of the above mentioned defect” by using a lens. You must mention the name of the lens used.
Answer:
(i) Hyperopia
(ii) Two reasons for the above defect are:
- Shortening of the eyeball
- Lens is too flat
(iii) Convex lens is used for the correction of Hyperopia. The diagram is shown below:

The diagram given alongside is the longitudinal section of a human kidney. Study the diagram and answer the questions that follow.

(i) Label the parts numbered 1 and 3.
(ii) Name the fluid that passes down from the part numbered as 4. Also write its main nitrogenous constituent.
(iii) Why does part 2 show a striped appearance?
Answer:
(i) The parts labelled 1 and 3 are:
- 1 → Cortex
- 3 → Pelvis
(ii) The fluid is urine. Its main nitrogenous constituent is Urea.
(iii) Henle's loops and collecting ducts lie in the medulla of kidneys giving it a striped appearance.
Answer:
Biodegradable waste | Non-biodegradable waste |
---|---|
Biodegradable wastes are substances which can be broken down by microorganisms into harmless and non-toxic substances. | Non-biodegradable wastes are substances which cannot be broken down by microorganisms. |
Examples: Leaves, dung. | Examples: Plastic, glass. |
Given below is the diagram of a human heart showing one phase of contraction. Study the same and answer the following questions.

(i) Label the parts numbered as 3 and 4.
(ii) What is the main difference between the blood flowing through the parts numbered as 1 and 2 ?
(iii) Write one important role of the part numbered as 5.
Answer:
(i) Parts numbered 3 and 4 are:
- 3 → Bicuspid valve
- 4 → Aortic Semilunar valve
(ii) Blood flowing through 1 (Pulmonary artery) is deoxygenated. Blood flowing through 2 (Aorta) is oxygenated.
(iii) Part 5 is pulmonary semilunar valve. It prevents backflow of blood into ventricles.
Answer:
Spermatogenesis | Oogenesis |
---|---|
Spermatogenesis is the process of production of sperms in seminiferous tubules. | Oogenesis is the process in which the ova producing cells give rise to the mature ovum. |
Spermatogenesis takes place in testis. | Oogenesis takes place in ovaries. |
The diagram given alongside represents a stage during the mitotic cell division. Study the same and answer the following questions.

(i) Identify the stage. Give reasons to support your answer.
(ii) Label the parts numbered 1 and 2.
(iii) Draw a neat and labelled diagram of the stage that comes before the stage shown in the figure.
Answer:
(i) The stage shown is Telophase as the daughter chromosomes have reached opposite poles, spindle fibres have started to disappear, nuclear membrane is formed and the cleavage furrow has started deepening.
(ii) Parts numbered 1 and 2 are:
- 1 → Chromosome
- 2 → Nuclear membrane
(iii) Anaphase is the stage that comes before Telophase. Diagram showing anaphase is given below:

Answer:
Nerve are a bundle of nerve fibres (axons) of separate neurons, enclosed in a tubular sheath while ganglion is the aggregate of the cytons or cell bodies of nerve cells from which the nerve fibres may arise or enter into.
The diagram given below is an experimental set-up to demonstrate a metabolic process in plants. Study same and answer the following questions.

(i) Name and define the physiological process being studied.
(ii) What is the aim of the above experiment?
(iii) Draw a neat diagram of an opened stoma and label the guard cells and stoma.
Answer:
(i) Transpiration
Transpiration is the loss of water in the form of water vapour from the aerial parts (leaves and stem) of the plant.
(ii) The aim of the above experiment is to demonstrate the different magnitudes of transpiration from the upper and lower surfaces of dicot leaf.
(iii) Below diagram shows an opened stoma with guard cells and stoma labelled:

Answer:
Turgidity is the state of a cell in which the cell wall is rigid and stretched by an increase in the volume of vacuoles due to the absorption of water. It provides rigidity to soft tissues of plant such as the leaves.
Answer:
(i) Diabetes insipidus
(ii) Diabetes mellitus
(iii) Myxoedema