Analytical Chemistry — Use of Ammonium & Sodium Hydroxide

Solutions for Chemistry, Class 10, ICSE

2004

2 questions

Question 1

Sodium hydroxide solution is added first in a small amount, then in excess to the aqueous salt solutions of:

  1. copper [II] sulphate
  2. zinc nitrate
  3. lead nitrate
  4. iron [III] sulphate

State in each case :

(i) the colour of the precipitate when NaOH is added in a small quantity;

(ii) the nature of the precipitate [i.e. soluble or insoluble] when NaOH is added in excess.

Answer

(i) The colour of the precipitate when NaOH is added in a small quantity are as follows —

  1. Pale blue — copper [II] sulphate
  2. White — zinc nitrate
  3. Chalky white — lead nitrate
  4. Reddish brown — iron [III] sulphate

(ii) the nature of the precipitate [i.e. soluble or insoluble] when NaOH is added in excess are as follows —

  1. Insoluble — copper [II] sulphate
  2. Soluble — zinc nitrate
  3. Soluble — lead nitrate
  4. Insoluble — iron [III] sulphate
2004

Answer:

Question 2

Write balanced equations for — (a) Aluminium (b) Zinc — is warmed with NaOH [caustic soda] soln.

Answer

  1. Aluminium
    2Al + 2NaOH + 2H2O ⟶ 2NaAlO2 + 3H2

  2. Zinc
    Zn + 2NaOH ⟶ Na2ZnO2 + H2

2004

Answer:

2005

1 question

Question 1

The questions below refers to the following salt solutions listed A to F:

A: Copper nitrate

B: Iron [II] sulphate

C: Iron [III] chloride

D: Lead nitrate

E: Magnesium sulphate

F: Zinc chloride

(i) Which soln. becomes a deep/inky blue colour when excess of ammonium hydroxide is added to it.

(ii) Which solution gives a white precipitate with excess ammonium hydroxide solution.

Answer

(i) A: Copper nitrate becomes a deep/inky blue colour when excess of ammonium hydroxide is added to it.

(ii) D: Lead nitrate gives a white precipitate with excess ammonium hydroxide solution.

2005

Answer:

2006

3 questions

Question 1

From the list of substances given — Ammonium sulphate, Lead carbonate, Chlorine, Copper nitrate, Ferrous sulphate — State a solution of the compound which gives a dirty green precipitate with sodium hydroxide.

Answer

Ferrous sulphate gives a dirty green precipitate with sodium hydroxide.

2006

Answer:

Question 2

Write a balanced equation for the reaction between aluminium oxide and sodium hydroxide solution.

Answer

Al2O3 + 2NaOH ⟶ 2NaAlO2 + H2O

2006

Answer:

Question 3

Give one test to distinguish between the following:

Iron [III] chloride soln. and Copper chloride soln.

Answer

Ammonium hydroxide can be used to distinguish between the two. Iron [III] chloride soln. forms reddish brown ppt. of Fe(OH)3 which is insoluble in excess of ammonium hydroxide whereas copper chloride soln. forms a blue ppt. of Cu(OH)2 which is soluble in excess of ammonium hydroxide.

2006

Answer:

2008

1 question

Question 1

The salt which in soln. gives a pale green precipitate with NaOH solution and a white ppt. with BaCl2 soln. is :

  1. Iron [III] sulphate
  2. Iron [II] sulphate
  3. Iron [II] chloride
  4. Iron [III] chloride

Answer

Iron [II] sulphate gives a pale green precipitate with NaOH solution and a white ppt. with BaCl2 soln.

2008

Answer:

2009

2 questions

Question 1

Find the odd one with reasons [valency is not a criterion] :

  1. Al(OH)3
  2. Pb(OH)2
  3. Mg(OH)2
  4. Zn(OH)2

Answer

Mg(OH)2
Reason — All others are amphoteric hydroxides.

2009

Answer:

Question 2

Identity the substance P based on the information given :

The deliquescent salt P, turns yellow on dissolving in water, and gives a reddish brown precipitate with sodium hydroxide solution.

Answer

Ferric chloride [Fe(Cl)3]

2009

Answer:

2010

2 questions

Question 1

Give an equation for —

  1. ZnO reacts with NaOH solution.
  2. Conversion of – Zn(NO3)2 to Zn(OH)2

Answer

  1. ZnO + 2NaOH ⟶ Na2ZnO2 + H2O
  2. Zn(NO3)2 + 2NaOH ⟶ Zn(OH)2 + 2NaNO3
2010

Answer:

Question 2

Select the correct answer from A, B, C —

A: Sodium hydroxide soln.
B: A weak acid
C: Dilute sulphuric acid.

The solution which with zinc sulphate solution will give a white precipitate.

Answer

A: Sodium hydroxide soln

2010

Answer:

2011

3 questions

Question 1

Choose the correct answer :

Hydroxide of this metal is soluble in NaOH solution.

  1. Magnesium
  2. Lead
  3. Silver
  4. Copper

Answer

Lead

2011

Answer:

Question 2

Sodium hydroxide solution is added to the solutions containing the ions mentioned in List 1.

List 1 —

  1. Pb2+
  2. Fe2+
  3. Zn2+
  4. Fe3+
  5. Cu2+
  6. Ca2+

The precipitates obtained are in list 2 —

A: Reddish brown
B: White insoluble in excess
C: Dirty green
D: White soluble in excess
E: White soluble in excess
F: Blue.

Match list 1 with list 2

Answer

List 1List 2
Pb2+D: White soluble in excess
Fe2+C: Dirty green
Zn2+E: White soluble in excess
Fe3+A: Reddish brown
Cu2+F: Blue
Ca2+B: White insoluble in excess
2011

Answer:

Question 3

Give balanced equations for —

(i) Zinc oxide dissolves in NaOH

(ii) Zinc is heated with NaOH solution

Answer

(i) ZnO + 2NaOH ⟶ Na2ZnO2 + H2O

(ii) Zn + 2NaOH ⟶ Na2ZnO2 + H2

2011

Answer:

2012

2 questions

Question 1

Name: The gas evolved on reaction of aluminium with boiling concentrated caustic alkali solution.

Answer

Hydrogen gas
2Al + 2NaOH + 2H2O ⟶ 2NaAlO2 + 3H2

2012

Answer:

Question 2

State one observation for:

  1. Excess NH4OH soln. is added to Pb(NO3)2
  2. NaOH soln. is added to FeCl3 soln. in excess.

Answer

  1. Chalky white insoluble precipitate is obtained.
    Pb(NO3)2 + 2NH4OH ⟶ 2NH4NO3 + Pb(OH)2

  2. Reddish brown insoluble precipitate is obtained.
    FeCl3 + 3NaOH ⟶ 3NaCl + Fe(OH)3

2012

Answer:

2013

1 question

Question 1

State two relevant observations for the reaction:

Ammonium hydroxide solution is added to copper (II) nitrate solution in small quantities and then in excess.

Answer

Two observations are:

  1. A bluish white ppt. is formed when small amount of ammonium hydroxide is added.
  2. This precipitate turns deep blue when excess of ammonium hydroxide solution is added.
2013

Answer:

2014

1 question

Question 1

State your observation: When excess sodium hydroxide is added to calcium nitrate solution.

Answer

White precipitate is obtained which is almost insoluble in excess of NaOH.

2014

Answer:

2015

1 question

Question 1

To a salt solution 'Y' a small quantity of NH4OH solution is added slowly and then in excess. A pale blue precipitate is formed which dissolves in ex­cess to form a clear inky blue solution. Identify the posi­tive ion in the salt 'Y'

Answer

Cu2+ ion.

2015

Answer:

2016

1 question

Question 1

State your observations when ammonium hydroxide solution is added drop by drop and then in excess to each of the following:

(i) copper sulphate solution

(ii) zinc sulphate solution.

Answer

(i) Pale blue precipitate of Cu(OH)2 is formed, which becomes deep blue when excess of ammonium hydroxide is added.

CuSO4 + 2NH4OH ⟶ (NH4)2SO4 + Cu(OH)2

Cu(OH)2 + (NH4)2SO4 + 2NH4OH [in excess] ⟶ 4H2O + [Cu(NH3)4]SO4

(ii) Gelatinous white precipitate of zinc hydroxide is formed which becomes colourless solution on adding excess of ammonium hydroxide.

ZnSO4 + 2NH4OH ⟶ (NH4)2SO4 + Zn(OH)2

Zn(OH)2 +(NH4)2SO4 + 2NH4OH [in excess] ⟶ 4H2O + [Zn(NH3)4]SO4

2016

Answer:

2017

2 questions

Question 1

State one relevant observation – Action of sodium hydroxide solution on iron [II] sulphate solution.

Answer

A dirty green precipitate is formed which is insoluble in excess of sodium hydroxide solution.

2017

Answer:

Question 2

How will you distinguish between — Ammonium Hydroxide & Sodium Hydroxide using CuSO4

Answer

CuSO4 forms a pale blue precipitate which is insoluble in excess of sodium hydroxide and with ammonium hydroxide it forms a pale blue precipitate which dissolves in excess of ammonium hydroxide and forms a deep/inky blue solution.

2017

Answer:

2018

3 questions

Question 1

Choose the correct answer from the options given :

The salt solution which does not react with ammonium hydroxide is :

  1. Calcium nitrate
  2. Zinc nitrate
  3. Lead nitrate
  4. Copper nitrate

Answer

Calcium nitrate
Reason — concentration of OH1- ions is low and so ppt. cannot be formed.

2018

Answer:

Question 2

Write a balanced chemical equation for :

(i) Reaction of sodium hydroxide solution with iron [III] chloride solution.

(ii) Reaction of zinc with potassium hydroxide solution.

Answer

(i) FeCl3 + 3NaOH ⟶ 3NaCl + Fe(OH)3

(ii) Zn + 2KOH ⟶ K2ZnO2 + H2

2018

Answer:

Question 3

State one relevant observation : Lead nitrate solution is treated with sodium hydroxide soln. drop wise, till it is in excess.

Answer

Chalky white precipitate is formed which is soluble in excess of sodium hydroxide and forms a colourless solution.

2018

Answer:

2019

2 questions

Question 1

Write balanced chemical equation for —

Ammonium hydroxide is added to ferrous sulphate solution.

Answer

2NH4OH + FeSO4 ⟶ (NH4)2SO4 + Fe(OH)2

2019

Answer:

Question 2

Copper [II] sulphate solution reacts with NaOH solution to form a precipitate of Cu(OH)2. State it's colour.

Answer

Pale blue precipitate is formed.

2019

Answer:

2020

1 question

Question 1

State one relevant observation for the reaction : Addition of excess ammonium hydroxide into copper sulphate solution.

Answer

Deep blue or inky blue solution is formed when excess of ammonium hydroxide is added to copper sulphate solution.

2020

Answer:

Additional Questions

6 questions

Question 1

Salts of ............... [normal/transitional] elements are generally coloured. From the ions K1+, Cr3+, Fe2+, Ca2+, SO32-, MnO41-, NO31- the ions generally coloured are ...............

Answer

Salts of transitional elements are generally coloured. From the ions K1+, Cr3+, Fe2+, Ca2+, SO32-, MnO41-, NO31- the ions generally coloured are Cr3+, Fe2+, MnO41- .

Additional Questions

Answer:

Question 2

The hydroxide which is soluble in excess of NaOH is ............... [Zn(OH)2/Fe(OH)3/Fe(OH)2]

Answer

The hydroxide which is soluble in excess of NaOH is Zn(OH)2

Additional Questions

Answer:

Question 3

The salt which will not react with NH4OH solution is ............... [ZnCl2/CuCl2/NH4Cl/FeCl2]

Answer

The salt which will not react with NH4OH solution is NH4Cl

Additional Questions

Answer:

Question 4

The substance/s which react with hot conc. NaOH soln. and undergoes a neutralization reaction ............... [Al2O3/Al/Al(OH)3]

Answer

The substance/s which react with hot conc. NaOH soln. and undergoes a neutralization reaction Al2O3.

Additional Questions

Answer:

Question 5

To distinguish soluble salts of zinc and lead, ............... [NaOH/NH4OH] can be used.

Answer

To distinguish soluble salts of zinc and lead NaOH can be used.

Additional Questions

Answer:

Question 6

Oxides and hydroxides of certain metals i.e ............... [iron/ zinc/copper/aluminium/magnesium/lead] are amphoteric and react with ............... [acids/alkalis/acids and alkalis] to give salt and water.

Answer

Oxides and hydroxides of certain metals i.e zinc, aluminium, lead are amphoteric and react with acids and alkalis to give salt and water.

Additional Questions

Answer:

Equation Worksheet

4 questions

Question 1

Action of Sodium Hydroxide — on solutions of saltsComplete and balance the equations
1a. Calcium nitrate andCa(NO3)2 + NaOH ⟶ ............... + ............... ↓
1b. Magnesium ChlorideMgCl2 + NaOH ⟶ ............... + ............... ↓
2. Iron [II] sulphateFeSO4 + NaOH ⟶ ............... + ............... ↓
3. Iron [III] chlorideFeCl3 + NaOH ⟶ ............... + ............... ↓
4. Copper [II] sulphateCuSO4 + NaOH ⟶ ............... + ............... ↓
5. Zinc sulphateZnSO4 + NaOH ⟶ ............... + ............... ↓

[Zn(OH)2 + NaOH [in excess] ⟶ ............... + ...............]
6. Lead nitratePb(NO3)2 + NaOH ⟶ ............... + ............... ↓

[Pb(OH)2 + NaOH [in excess] ⟶ ............... + ...............]

Answer

Action of Sodium Hydroxide — on solutions of saltsComplete and balance the equations
1a. Calcium nitrate andCa(NO3)2 + 2NaOH ⟶ 2NaNO3 + Ca(OH)2
1b. Magnesium ChlorideMgCl2 +2NaOH ⟶ 2NaCl + Mg(OH)2
2. Iron [II] sulphateFeSO4 + 2NaOH ⟶ Na2SO4 + Fe(OH)2
3. Iron [III] chlorideFeCl3 + 3NaOH ⟶ 3NaCl + Fe(OH)3
4. Copper [II] sulphateCuSO4 + 2NaOH ⟶ Na2SO4 + Cu(OH)2
5. Zinc sulphateZnSO4 + 2NaOH ⟶ Na2SO4 + Zn(OH)2

[Zn(OH)2 + 2NaOH [in excess] ⟶ 2H2O + Na2ZnO2]
6. Lead nitratePb(NO3)2 + 2NaOH ⟶ 2NaNO3 + Pb(OH)2

[Pb(OH)2 + 2NaOH [excess] ⟶ 2H2O + Na2PbO2]
Equation Worksheet

Answer:

Question 2

Action of Ammonium Hydroxide — on solutions of salts   
7. Magnesium chlorideMgCl2 + NH4OH ⟶ ............... + ............... ↓
8. Iron [II] sulphateFeSO4 + NH4OH ⟶ ............... + ............... ↓
9. Iron [III] chlorideFeCl3 + NH4OH ⟶ ............... + ............... ↓
10. Copper [II] sulphateCuSO4 + NH4OH ⟶ ............... + ............... ↓

[Cu(OH)2 + (NH4)2SO4 + NH4OH [in excess] ⟶ ............... + ............... ]
11. Zinc sulphateZnSO4 + NH4OH ⟶ ............... + ............... ↓

[Zn(OH)2 +(NH4)2SO4 + NH4OH [in excess] ⟶ ............... + ...............]
12. Lead nitratePb(NO3)2 + NH4OH ⟶ ............... + ............... ↓

Answer

Action of Ammonium Hydroxide — on solutions of salts   
7. Magnesium chlorideMgCl2 + 2NH4OH ⟶ 2NH4Cl + Mg(OH)2
8. Iron [II] sulphateFeSO4 + 2NH4OH ⟶ (NH4)2SO4 + Fe(OH)2
9. Iron [III] chlorideFeCl3 + 3NH4OH ⟶ 3NH4Cl + Fe(OH)3
10. Copper [II] sulphateCuSO4 + 2NH4OH ⟶ (NH4)2SO4 + Cu(OH)2

[Cu(OH)2 + (NH4)2SO4 + 2NH4OH [in excess] ⟶ 4H2O + [Cu(NH3)4]SO4]
11. Zinc sulphateZnSO4 + 2NH4OH ⟶ (NH4)2SO4 + Zn(OH)2

[Zn(OH)2 +(NH4)2SO4 + 2NH4OH [in excess] ⟶ 4H2O + [Zn(NH3)4]SO4]
12. Lead nitratePb(NO3)2 + 2NH4OH ⟶ 2NH4NO3 + Pb(OH)2
Equation Worksheet

Answer:

Question 3

Action of Alkalis — on certain metals   
13. ZincZn + NaOH ⟶ ............... + ...............
14. ZincZn + KOH ⟶ ............... + ...............
15. LeadPb + NaOH ⟶ ............... + ...............
16. LeadPb + KOH ⟶ ............... + ...............
17. AluminiumAl + NaOH + H2O ⟶ ............... + ...............
18. AluminiumAl + KOH + H2O ⟶ ............... + ...............

Answer

Action of Alkalis — on certain metals   
13. ZincZn + 2NaOH ⟶ Na2ZnO2 + H2
14. ZincZn + 2KOH ⟶ K2ZnO2 + H2
15. LeadPb + 2NaOH ⟶ Na2PbO2 + H2
16. LeadPb + 2KOH ⟶ K2PbO2 + H2
17. Aluminium2Al + 2NaOH + 2H2O ⟶ 2NaAlO2 + 3H2
18. Aluminium2Al + 2KOH + 2H2O ⟶ 2KAlO2 + 3H2
Equation Worksheet

Answer:

Question 4

Action of Alkalis — on oxides and hydroxides of certain metals   
19. Zinc oxideZnO + NaOH ⟶ ............... + ...............
20. Zinc hydroxideZn(OH)2 + NaOH ⟶ ............... + ...............
21. Lead [II] oxidePbO + NaOH ⟶ ............... + ...............
22. Lead hydroxidePb(OH)2 + NaOH ⟶ ............... + ...............
23. Aluminium oxideAl2O3 + NaOH ⟶ ............... + ...............
24. Aluminium hydroxideAl(OH)3 + KOH ⟶ ............... + ...............

Answer

Action of Alkalis — on oxides and hydroxides of certain metals   
19. Zinc oxideZnO + 2NaOH ⟶ Na2ZnO2 + H2O
20. Zinc hydroxideZn(OH)2 + 2NaOH ⟶ Na2ZnO2 + 2H2O
21. Lead [II] oxidePbO + 2NaOH ⟶ Na2PbO2 + H2O
22. Lead hydroxidePb(OH)2 + 2NaOH ⟶ Na2PbO2 + 2H2O
23. Aluminium oxideAl2O3 + 2NaOH ⟶ 2NaAlO2 + H2O
24. Aluminium hydroxideAl(OH)3 + KOH ⟶ KAlO2 + 2H2O
Equation Worksheet

Answer: