CBSE Class 10 Maths: Surface Areas & Volumes — Notes 2026
Tushar Parik
Author
CBSE Class 10 Maths: Surface Areas & Volumes — Notes 2026
This comprehensive guide from Bright Tutorials covers everything you need to know — with clear explanations, exam tips, and key points for board exam preparation.
In This Article
Cube and Cuboid
- Cuboid: SA = 2(lb + bh + lh); V = lbh; diagonal = √(l²+b²+h²)
- Cube: SA = 6a²; V = a³; diagonal = a√3
- CBSE: paint/wallpaper (SA), packing/filling (volume) word problems
Cylinder
- CSA = 2πrh; TSA = 2πr(r+h); V = πr²h
- Hollow cylinder: volume = π(R²−r²)h; used in pipes, straw problems
- CBSE: water tank capacity, metal rod to cylinder, cylinder made from rectangular sheet
Cone
- Slant height l = √(h²+r²); CSA = πrl; TSA = πr(l+r); V = ⅓πr²h
- CBSE: canvas required for conical tent (CSA); volume of material in solid cone
- Cone inverted and filled with water — find volume of water
Sphere and Hemisphere
- Sphere: SA = 4πr²; V = (4/3)πr³
- Hemisphere: CSA = 2πr²; TSA = 3πr²; V = (2/3)πr³
- Hollow sphere: V = (4/3)π(R³−r³); used in ball bearings, hollow metal spheres
Frustum of Cone
- CSA = π(R+r)l; l = √[h²+(R−r)²]; TSA = πl(R+r)+π(R²+r²)
- V = (πh/3)(R²+r²+Rr)
- CBSE: bucket (frustum) capacity; wax candle frustum; earthen pots
Conversion of Solids
- Melting/recasting: volumes equal; change in dimensions calculated
- n small spheres from one large sphere: R³ = nr³; find r or n
- CBSE: metallic sphere melted to form wire of radius r and length l; cone melted to sphere
CBSE Exam Numericals
- A toy is in form of hemisphere of radius 3.5 cm surmounted by cone of same radius; height of cone = 4 cm. Find TSA
- Frustum with R=12 cm, r=3 cm, h=10 cm; find volume and CSA
- Water flowing through cylindrical pipe at 2 m/s fills tank in 30 min; find volume of tank
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