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CBSE Class 10 Science Question 8 of 41

Electricity — Question 8

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Question

Question 8

When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.

Answer

Given,

V = 12 V

I = 2.5 mA = 2.5 x 10-3A

R = ?

According to Ohm's Law:

V = IR

∴R=VI⇒R=122.5×10−3⇒R=4.8×103Ω\therefore \text{R} = \dfrac{\text{V}}{\text{I}} \\[1em] \Rightarrow \text{R} = \dfrac{12}{2.5 \times 10^{-3}} \\[1em] \Rightarrow \text{R} = 4.8 \times 10^{3} \Omega

Hence, resistance of the resistor = 4.8 kΩ