Question 2A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located?

Question

Accepted Answer

Given, object distance (u) = -10 cmMagnification = -3 (as the image is real and inverted)image distance (v) = ?We know,Magnification=−vu=height of imageheight of object\text{Magnification} = \dfrac{-v}{u} = \dfrac{\text{height of image}}{\text{height of object}} \[1em]Magnification=u−v​=height of objectheight of image​Substituting we get,−3=−v−10⇒−v=(−3)×(−10)⇒v=−30 cm-3 = \dfrac{-v}{-10} \[1em] \Rightarrow -v = (-3) \times (-10) \[1em] \Rightarrow v = -30 \text{ cm}−3=−10−v​⇒−v=(−3)×(−10)⇒v=−30 cmThe negative sign indicates that an inverted image is formed in front of the given concave mirror at a distance of 30 cm.

Light - Reflection and Refraction — Question 2

Question 2