Data Representation — Question 9

Grouping in bits of 4:

$\underlinesegment{0001} \quad \underlinesegment{0101} \quad \underlinesegment{1011} \quad \underlinesegment{0111}$

Therefore, (1010110110111)₂ = (15B7)₁₆

(b) 10110111011011

Grouping in bits of 4:

$\underlinesegment{0010} \quad \underlinesegment{1101} \quad \underlinesegment{1101} \quad \underlinesegment{1011}$

Therefore, (10110111011011)₂ = (2DDB)₁₆

(c) 0110101100

Grouping in bits of 4:

$\underlinesegment{0001} \quad \underlinesegment{1010} \quad \underlinesegment{1100}$

Therefore, (0110101100)₂ = (1AC)₁₆