Question 37(c)Predict the output of the following code.def code(n):
if n == 0:
print(' Finally')
else:
print (n)
code (10)

Question

Question 37(c)Predict the output of the following code.def code(n):
    if n == 0:
       print(' Finally') 
    else:
       print (n)
code (10)

Bright Tutorials · Accepted Answer

Output10
ExplanationThis code defines a function called code(n) that takes a single argument n. Inside the function, there's a conditional statement that checks if n is equal to 0. If n is indeed 0, it prints the string " Finally". Otherwise, it prints the value of n. When the function code(10) is called, it passes the argument 10 to the function. Since 10 is not equal to 0, the function prints 10.

Functions — Question 43

Question 37(c)

Output

Explanation