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Question A theatre company can accommodate 45 people during one show.
(a) A total of 475 people bought tickets for a puppet show. How many shows are needed to seat all the people who bought tickets?
(b) There are 2 shows in a day. How many days will be needed to accommodate all the people?
(a) The number of shows required for 475 people
= 475 ÷ 45
Ten shows will accommodate 450 people and one more show will accommodate for the remaining 25 people.
Therefore, 11 shows are needed to seat all the people who bought tickets.
(b) From part (a) number of shows required is 11.
If there are 2 shows in a day, then in 5 days there will be 10 shows, and on 6th day the 11th show will be held.
Thus, 6 days are needed to accommodate all the people.