\(\frac{2}{7}+\frac{5}{7}+\frac{6}{7}\)
= \(\frac{2+5+6}{7}=\frac{13}{7}\)
=1 \(\frac{6}{7}\)
(b) \(\frac{3}{4}+\frac{1}{3}\)
Solution:
\(\frac{3}{4}+\frac{1}{3}=\frac{3}{4} \times \frac{3}{3}+\frac{1}{3} \times \frac{4}{4}\)
= \(\frac{9}{12}+\frac{4}{12}=\frac{9+4}{12}\)
= \(\frac{13}{12}\)
= 1 \(\frac{1}{12}\)
(c) \(\frac{2}{3}+\frac{5}{6}\)
Solution:
\(\frac{2}{3}+\frac{5}{6}=\frac{2}{3} \times \frac{2}{2}+\frac{5}{6}\)
\(\frac{4}{6}+\frac{5}{6}=\frac{9}{6}=\frac{3}{2}\)
= 1 \(\frac{1}{2}\)
(d) \(\frac{2}{3}+\frac{2}{7}\)
Solution:
\(\frac{2}{3}+\frac{2}{7}=\frac{2}{3} \times \frac{7}{7}+\frac{2}{7} \times \frac{3}{3}\)
= \(\frac{14}{21}+\frac{6}{21}=\frac{20}{21}\)
(e) \(\frac{3}{4}+\frac{1}{3}+\frac{1}{5}\)
Solution:
\(\frac{45}{60}+\frac{20}{60}+\frac{12}{60}\)
= \(\frac{77}{60}\)
= 1\(\frac{17}{60}\)
(f) \(\frac{2}{3}+\frac{4}{5}\)
Solution:
\(\frac{10}{15}+\frac{12}{15}=\frac{22}{15}\)
= 1\(\frac{7}{15}\)
(g) \(\frac{4}{5}+\frac{2}{3}\)
Solution:
\(\frac{12}{15}+\frac{10}{15}=\frac{22}{15}\)
= 1\(\frac{7}{15}\)
(h) \(\frac{3}{5}+\frac{5}{8}\)
Solution:
\(\frac{24}{40}+\frac{25}{40}=\frac{49}{40}\)
= \(\frac{9}{40}\)
(i) \(\frac{9}{2}+\frac{5}{4}\)
Solution:
\(\frac{18}{4}+\frac{5}{4}=\frac{23}{4}\)
= 5\(\frac{3}{4}\)
(j) \(\frac{8}{3}+\frac{2}{7}\)
Solution:
\(\frac{56}{21}+\frac{6}{21}=\frac{62}{21}\)
= 2\(\frac{20}{21}\)
(k) \(\frac{3}{4}+\frac{1}{3}+\frac{1}{5}\)
Solution:
\(\frac{45}{60}+\frac{20}{60}+\frac{12}{60}=\frac{77}{60}\)
= 1\(\frac{17}{60}\)
(l) \(\frac{2}{3}+\frac{4}{5}+\frac{3}{7}\)
Solution:
\(\frac{70}{105}+\frac{84}{105}+\frac{45}{105}=\frac{199}{105}\)
= 1\(\frac{94}{105}\)
(m) \(\frac{9}{2}+\frac{5}{4}+\frac{7}{6}\)
Solution:
\(\frac{54}{12}+\frac{15}{12}+\frac{14}{12}=\frac{83}{12}\)
= \(\frac{11}{12}\)