Given \(\frac{8}{15}-\frac{3}{15}\)
Fractional unit for both fractions is \(\frac{1}{15}\) then
\(\frac{8}{15}-\frac{3}{15}=\frac{8-3}{15}\)
= \(\frac{5}{15}=\frac{1}{3}\)
(b) \(\frac{2}{5}-\frac{4}{15}\)
Solution:
Given \(\frac{2}{5}-\frac{4}{15}\)
Here LCM of 5 and 15 is 15. Fractional unit for both fractions should be \(\frac{1}{15}\)
then \(\frac{2 \times 3}{5 \times 3}-\frac{4 \times 1}{15 \times 1}\)
= \(\frac{6}{15}-\frac{4}{15}\)
= \(\frac{6-4}{15}\)
= \(\frac{2}{15}\)
(c) \(\frac{5}{6}-\frac{4}{9}\)
Solution:
Given \(\frac{5}{6}-\frac{4}{9}\)
Hence LCM of 6 and 9 is 18. Fractional unit for both fractions should be \(\frac{1}{18}\) then
(d) \(\frac{2}{3}-\frac{1}{2}\)
Solution:
Given \(\frac{2}{3}-\frac{1}{2}\)
Here LCM of 3 and 2 is 6. Fractional unit for both fractions should be \(\frac{1}{6}\)