CBSE Class 6 Mathematics Question 45 of 48

Prime Time — Question 46

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46
Question
Find the remainders obtained when each of the following numbers are divided by (i) 10 (ii) 5 (iii) 2. 78, 99, 173, 572, 980, 1111, 2345
Answer

Here we have to divide 78 by 10, 5 and
2 then
Now do yourself:
99/10: Remainder = 9, 99/5: Remainder = 4, 99/2: Remainder = 1
173/10: Remainder = 3, 173/5: Remainder = 3, 173/2: Remainder = 1
572/10: Remainder = 2, 572/5: Remainder = 2, 572/2: Remainder = 0
980/10: Remainder = 0,980/5: Remainder = 0, 980/2: Remainder = 0
1111/10: Remainder= 1,1111/5: Remainder= 1, 1111/2: Remainder = 1
2345/10: Remainder 5,2345/5: Remainder = 0, 2345/2: Remainder = 1