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Question I am a 3-digit number. My hundred’s digit is 3 less than my ten’s digit. My ten’s digit is 3 less than my unit’s digit. The sum of all three digits is 15. Who am I?
Let the ten’s place digit be x. Then hundred’s place digit = x – 3 Unit’s digit = x + 3 Sum of digits = 15 According to the question, (x – 3) + x + (x + 3) = 15 ⇒ 3x = 15 Divide both sides by 3 \(\frac{3 x}{3}=\frac{15}{3}\) ⇒ x = 5 Ten’s digit = 5 Hundred’s digit = 5 – 3 = 2 Unit’s digit = 5 + 3 = 8 Number formed = 258