Finding the Unknown — Question 5

Let the number be x. According to the question, \(\frac {1}{4}\) × x + 9 = x \(\frac {x}{4}\) + 9 = x Subtract \(\frac {x}{4}\) from both sides \(\frac{x}{4}+9-\frac{x}{4}=\frac{x}{1}-\frac{x}{4}\) ⇒ 9 = \(\frac{4 x-x}{4}\) [LCM of 1 and 4 = 4] ⇒ 9 = \(\frac {3x}{4}\) Divide both sides by \(\frac {3}{4}\) ⇒ \(9 \div \frac{3}{4}=\frac{3 x}{4} \div \frac{3}{4}\) ⇒ \(9 \times \frac{4}{3}=\frac{3 x}{4} \times \frac{4}{3}\) ⇒ 12 = x The required number is 12.