A dart-throwing competition was organised inaschool. The number of throws participants took to hit the bull’s eye (the centre circle) is given in the table below. Describe the data using its minimum, maximum, mean, and median.

Question

Bright Tutorials · Accepted Answer

The minimum number of trials is 1.
The maximum number of trials is 10.
Mean = $\begin{gathered}
(1 \times 1)+(2 \times 0)+(3 \times 0)+(4 \times 1) \
+(5 \times 4)+(6 \times 9)+(7 \times 12)+ \
(8 \times 15)+(9 \times 10)+(10 \times 10) \
\hline 62
\end{gathered}$
= $\begin{gathered}
1+0+0+4+20+54+84 \
+120+90+100 \
\hline 62
\end{gathered}$
= $\frac {473}{62}$
= 7.6 trials
Median:
Median = average of $\left(\frac{62}{2}\right)^{t h}$ term and $\left(\frac{62}{2}+1\right)^{t h}$ term
= average of 31th and 32th terms
The 31st and 32nd terms lie in the cumulative frequency corresponding to 8.
5.2 Visualising and Interpreting Data
Figure It Out (Pages 122-123)

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