Tales by Dots and Lines — Question 10
Back to all questionsFrom the dot plot Data (i) Sum = (0 × 3) + (1 × 1) + (2 × 4) + (3 × 7) + (4 × 7) + (5 × 5) + (6 × 4) + (7 × 6) + (8 × 3) + (10 × 2) = 0 + 1 + 8 + 21 + 28 + 25 + 24 + 42 + 24 + 20 = 193 Total number of students = 42 Average = \(\frac {193}{42}\) = 4.59 times (ii) Total number of students = 42 (even) So Median = average of 21st and 22nd terms The 21st and 22nd terms lie in the cumulative frequency corresponding to 4. So median = \(\frac{4+4}{2}\) = 4 Median number of times students rode their cycles = 4 (iii) (a) Invalid (b) Valid (c) Valid (d) Invalid (e) Next week’s mean and median will be Mean = previous mean + 1 = 4.59 + 1 = 5.59 Median: Now the 21st and 22nd terms lie in the cumulative frequency corresponding to 5. So Median = \(\frac{5+5}{2}\) = 5