Simplify the following expression:
(3+3)(2+2)(3 + \sqrt{3}) (2 + \sqrt{2})(3+3)(2+2)
= 3 x 2 + 3 x 2\sqrt{2}2 + 2 x 3\sqrt{3}3 + 3\sqrt{3}3 x 2\sqrt{2}2
= 6 + 3 2\sqrt{2}2 + 2 3\sqrt{3}3 + 6\sqrt{6}6
Hence, (3+3)(2+2)=6+32+23+6(3 + \sqrt{3}) (2 + \sqrt{2}) = 6 + 3\sqrt{2} + 2\sqrt{3} + \sqrt{6}(3+3)(2+2)=6+32+23+6
