Surface Areas and Volumes — Question 9

On revolving,

Triangle around side 12 cm it becomes a cone with height 12 cm.

From figure,

Radius of the cone (r) = 5 cm

Height of the cone (h) = 12 cm

Volume of the cone (V) = $\dfrac{1}{3}πr^2h$

Substituting values we get :

$V = \dfrac{1}{3} \times π \times 5^2 \times 12 \\[1em] = \dfrac{1}{3} \times π \times 25 \times 12 \\[1em] = 100π\text{ cm}^3$

Hence, the volume of the cone is 100π cm³.