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ICSE Class 10 Chemistry Question 17 of 25

Gay Lussac's Law — Avogadro's Law — Mole Concept — Question 17

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Question

Question 17

Calculate the moles of sodium hydroxide contained in 160 g of it. [Na = 23, O = 16, H = 1]

Answer

Gram molecular mass of sodium hydroxide
= Na + O + H
= 23 + 16 + 1
= 40 g

As, 40 g of sodium hydroxide = 1 mole

∴ 160 g of sodium hydroxide = 140×160=4 moles\dfrac{ 1}{40} \times 160 = 4 \text{ moles}

Hence, number of moles in 160 g of sodium hydroxide is 4