ICSE Class 10 Chemistry Question 18 of 25

Gay Lussac's Law — Avogadro's Law — Mole Concept — Question 18

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18
Question

Question 18

Calculate the weight in g. of 2.5 moles of ethane [C2H6]. [C = 12, H = 1]

Answer

Gram molecular mass of C2H6 = (2 x 12) + (6 x 1)
= 24 + 6
= 30 g

1 mole of C2H6 weighs 30 g

∴ 2.5 moles weighs = 301×2.5=75 g\dfrac{ 30}{1} \times 2.5 = 75 \text{ g}

Hence, weight of 2.5 moles of ethane [C2H6] is 75 g.