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ICSE Class 10 Chemistry Question 19 of 25

Gay Lussac's Law — Avogadro's Law — Mole Concept — Question 19

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Question

Question 19

Calculate the molecular weight of 2.6 g of a gas which occupies 2.24 lits. at 0°C and 760 mm press.

Answer

Given,

2.24 lit volume of gas weighs 2.6 g

∴ 22.4 lit volume of gas weighs = 2.62.24×22.4=26 g\dfrac{2.6}{2.24} \times 22.4 = 26 \text{ g}

As 22.4 lit of gas at s.t.p. weighs 26 g
∴ Molecular weight = 26 g