Mole Concept and Stoichiometry — Question 24

Molar mass of urea [CO(NH₂)₂] = 12 + 16 + 2(14 + (2 x 1))

= 28 + 2(16)

= 28 + 32

= 60 g

Molar mass of nitrogen = 2 x 14 = 28 g

60 g urea has mass of nitrogen = 28 g

∴ 5000 g urea will have mass

= $\dfrac{28 \times 5000 }{60}$

= 2333 g = 2.33 kg