Calculate the volume occupied by 320 g of sulphur dioxide at S.T.P.
[S = 32; O = 16]
Molar mass of sulphur dioxide (SO2) = S + 2O = 32 + (2 x 16) = 32 + 32 = 64 g
64 g of sulphur dioxide has volume = 22.4 litre
∴ 320 g of sulphur dioxide will have volume = 22.4×32064\dfrac{22.4\times 320}{64}6422.4×320
= 112 litres
