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ICSE Class 10 Chemistry Question 4 of 93

Organic Chemistry — Question 16

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Question

Question 15.2

Give equations for the conversions of – Ethene, Ethyne to:

EtheneEthyne  
(a) Ethane(a) Ethane [2 steps ]by - Catalytic hydrogenation - H2
(b) 1,2 dichloroethane(b) 1,1,2,2 tetrachloroethane [2 steps]by- Halogenation - Cl2
(c) 1,2 dibromoethane(c) 1,1,2,2 tetrabromoethane [2 steps]- Br2
(d) 1,2 diiodoethane(d) 1,2 diiodoethene- I2
(e) Bromoethane/Chloroethane(e) 1,1 -dibromo & 1,1-dichloroethaneby- Halogen acids - HBr/HCl
by - Polymerization
(f) Polyethylene(f) Copper or silver Acetylideby Ammoniacal - CuCl/AgNO3
Answer

(a) Conversion of Ethene to Ethane by Catalytic hydrogenation (H2):

C2H4 ethene+H2→300°CNickleC2H6ethane\underset{\text{ ethene}}{\text{C}_2\text{H}_4} + \text{H}_2 \xrightarrow[300\degree\text{C}]{\text{Nickle}} \underset{\text{ethane}}{\text{C}_2\text{H}_6}

(b) Conversion of Ethene to 1,2 dichloroethane by Halogenation (Cl2):

Give equations for the conversions of Ethene to 1,2 dichloroethane by Halogenation. Organic Chemistry, Simplified Chemistry Dalal Solutions ICSE Class 10

(c) Conversion of Ethene to 1,2 dibromoethane by Halogenation (Br2):

Give equation for the conversion of Ethene to 1,2 dibromoethane by Halogenation. Organic Chemistry, Simplified Chemistry Dalal Solutions ICSE Class 10.

(d) Conversion of Ethene to 1,2 diiodoethane by Halogenation (I2):

C2H4 ethene+I2→[inert solvent]CCl4C2H4I21,2, di iodoethane\underset{\text{ ethene}}{\text{C}_2\text{H}_4} + \text{I}_2 \xrightarrow[\text{[inert solvent]}]{\text{CCl}_4} \underset{\text{1,2, di iodoethane}}{\text{C}_2\text{H}_4\text{I}_2}

(e)(i) Conversion of Ethene to Bromoethane by Halogen acids (HBr):

C2H4 ethene+HBr⟶CH3CH2BrBromoethane\underset{\text{ ethene}}{\text{C}_2\text{H}_4} + \text{HBr} \longrightarrow \underset{\text{Bromoethane}}{\text{CH}_3\text{CH}_2\text{Br}}

(e)(ii) Conversion of Ethene to Chloroethane by Halogen acids (HCl):

C2H4ethene+HCl⟶CH3CH2ClChloroethane\underset{\text{ethene}}{\text{C}_2\text{H}_4} + \text{HCl} \longrightarrow \underset{\text{Chloroethane}}{\text{CH}_3\text{CH}_2\text{Cl}}

(f) Conversion of Ethene to Polyethylene by Polymerization:

Ethene polymerises to produce polythene

n H2C = CH2ethene→high pressure catalysthigh temperature[H2C—CH2]n(Polythene)\underset{\text{ethene}}{\text{n H}_2\text{C = C}\text{H}_2} \xrightarrow[\text{high pressure catalyst}]{\text{high temperature}} \underset{\text{(Polythene)}}{\Big[\text{H}_2\text{C—C}\text{H}_2\Big]_\text{n}}

(a) Conversion of Ethyne to Ethane [2 steps] by Catalytic hydrogenation (H2):

Give equation for the conversion of Ethyne to Ethane [2 steps] by Catalytic hydrogenation. Organic Chemistry, Simplified Chemistry Dalal Solutions ICSE Class 10.

(b) Conversion of Ethyne to 1,1,2,2 tetrachloroethane [2 steps] by Halogenation (Cl2):

Give equation for the conversion of Ethyne to 1,1,2,2 tetrachloroethane [2 steps] by Halogenation. Organic Chemistry, Simplified Chemistry Dalal Solutions ICSE Class 10

(c) Conversion of Ethyne to 1,1,2,2 tetrabromoethane [2 steps] by Halogenation (Br2):

Give equation for the conversion of Ethyne to 1,1,2,2 tetrabromoethane [2 steps] by Halogenation. Organic Chemistry, Simplified Chemistry Dalal Solutions ICSE Class 10

(d) Conversion of Ethyne to 1,2 diiodoethene by Halogenation (I2):

HC ≡ CH ethyne+I2→alcoholH — CI∣=CI∣ — H1,2 di iodoethene\underset{\text{ ethyne}}{\text{HC ≡ CH}} + \text{I}_2 \xrightarrow{\text{alcohol}} \underset{\text{1,2 di iodoethene}}{\text{H — } \overset{\underset{\normalsize{|}}{\normalsize{I}}}{\text{C}} = \overset{\underset{\normalsize{|}}{\normalsize{I}}}{\text{C}} \text{ — H}}

(e)(i) Conversion of Ethyne to 1,1 dibromo ethane by Halogen acids (HBr):

Give equation for the conversion of Ethyne to 1,1 dibromo ethane by Halogen acids. Organic Chemistry, Simplified Chemistry Dalal Solutions ICSE Class 10.

(e)(ii) Conversion of Ethyne to 1,1 dichloro ethane by Halogen acids (HCl):

Give equation for the conversion of Ethyne to 1,1 dichloro ethane by Halogen acids. Organic Chemistry, Simplified Chemistry Dalal Solutions ICSE Class 10.

(f)(i) Conversion of Ethyne to Copper Acetylide by Ammoniacal Cuprous Chloride:

HC ≡ CH ethyne+2CuCl+2NH4OH⟶Cu-C ≡ C-CuCopper Acetylide+2NH4Cl+2H2O\underset{\text{ ethyne}}{\text{HC ≡ CH}} + 2\text{CuCl} + 2\text{NH}_4\text{OH} \longrightarrow \underset{\text{Copper Acetylide}}{\text{Cu-C ≡ C-Cu}} + 2\text{NH}_4\text{Cl} + 2\text{H}_2\text{O}

(f)(ii) Conversion of Ethyne to Silver Acetylide by Ammoniacal Silver Nitrate:

HC ≡ CH ethyne+2AgNO3+2NH4OH⟶Ag-C ≡ C-AgSilver Acetylide+2NH4NO3+2H2O\underset{\text{ ethyne}}{\text{HC ≡ CH}} + 2\text{AgNO}_3 + 2\text{NH}_4\text{OH} \longrightarrow \underset{\text{Silver Acetylide}}{\text{Ag-C ≡ C-Ag}} + 2\text{NH}_4\text{NO}_3 + 2\text{H}_2\text{O}