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ICSE Class 10 Chemistry Question 32 of 93

Organic Chemistry — Question 2

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Question

Question 2(2008)

Name the organic compound prepared by each of the following reactions :

(i) C2H5COONa + NaOH ⟶

(ii) CH3I + 2[H]⟶

(iii) C2H5Br + KOH (alcoholic soln.) ⟶

(iv) CaC2 + 2H2O ⟶

Answer

(i) Ethane

C2H5COONasodium propionate+NaOHsodalime→CaOΔC2H6ethane+Na2CO3\underset{\text{sodium propionate}}{\text{C}_2\text{H}_5\text{COONa}} + \underset{\text{sodalime}}{\text{NaOH}} \underset{\Delta}{\xrightarrow{\text{CaO}}} \underset{\text{ethane}}{\text{C}_2\text{H}_6} + \text{Na}_2\text{CO}_3

(ii) Methane

CH3Imethyl iodide+2[H]nascent hydrogen→alcoholZn/Cu coupleCH4methane+HI\underset{\text{methyl iodide}}{\text{CH}_3\text{I}} + \underset{\text{nascent hydrogen}}{2\text{[H]}} \xrightarrow[\text{alcohol}]{\text{Zn/Cu couple}} \underset{\text{methane}}{\text{CH}_4} +\text{HI}

(iii) Ethene [ethylene]

C2H5Br Bromo ethane [ethyl bromide]+KOHalcoholic→boilH2C=CH2ethene [ethylene]+KBr+H2O\underset{\text{ Bromo ethane [ethyl bromide]}}{\text{C}_2\text{H}_5\text{Br}} + \underset{\text{alcoholic}}{\text{KOH}} \xrightarrow{\text{boil}} \underset{\text{ethene [ethylene]}}{\text{H}_2\text{C}=\text{C}\text{H}_2} + \text{KBr} + \text{H}_2\text{O}

(iv) Ethyne [Acetylene]

CaC2calcium carbide+2H2Owater⟶C2H2ethyne [acetylene]+Ca(OH)2\underset{\text{calcium carbide}}{\text{CaC}_2} + \underset{\text{water}}{2\text{H}_2\text{O}} \longrightarrow \underset{\text{ethyne [acetylene]}}{\text{C}_2\text{H}_2} + \text{Ca(OH)}_2