(i) By boiling ethyl chloride with aqueous NaOH.
C 2 H 5 -Cl Chloroethane [ethyl chloride] + NaOH [aq.] → boil C 2 H 5 OH Ethanol [ethyl alcohol] + NaCl \underset{\text{ Chloroethane [ethyl chloride]}}{\text{C}_2\text{H}_5\text{-Cl}} + \text{NaOH [aq.]} \xrightarrow{\text{boil}} \underset{\text{ Ethanol [ethyl alcohol]}}{\text{C}_2\text{H}_5\text{OH}} + \text{NaCl} Chloroethane [ethyl chloride] C 2 H 5 -Cl + NaOH [aq.] boil Ethanol [ethyl alcohol] C 2 H 5 OH + NaCl
(ii) By boiling ethyl chloride with alcoholic KOH.
C 2 H 5 -Cl Chloroethane [ethyl chloride] + KOH [aq.] alcoholic KOH → boil C 2 H 4 Ethene [ethylene] + KCl + H 2 O \underset{\text{ Chloroethane [ethyl chloride]}}{\text{C}_2\text{H}_5\text{-Cl}} + \underset{\text{ alcoholic KOH}}{\text{KOH [aq.]}} \xrightarrow{\text{boil}} \underset{\text{ Ethene [ethylene]} }{\text{C}_2\text{H}_4} + \text{KCl} +\text{H}_2\text{O} Chloroethane [ethyl chloride] C 2 H 5 -Cl + alcoholic KOH KOH [aq.] boil Ethene [ethylene] C 2 H 4 + KCl + H 2 O
(iii) Ethene is absorbed in conc. sulphuric acid at 80 °C under 30 atmos. to give ethyl hydrogen sulphate, which on hydrolysis with steam gives ethanol.
C 2 H 4 Ethene + H 2 SO 4 conc. → 80 ° C 30 atmos. C 2 H 5 -HSO 4 Ethyl hydrogen sulphate \underset{\text{ Ethene} }{\text{C}_2\text{H}_4} + \underset{\text{conc.}}{\text{H}_2\text{SO}_4} \underset{30 \text{ atmos.}}{\xrightarrow{80 \degree \text{C}}} \underset{\text{ Ethyl hydrogen sulphate} }{\text{C}_2\text{H}_5\text{-HSO}_4} Ethene C 2 H 4 + conc. H 2 SO 4 30 atmos. 80° C Ethyl hydrogen sulphate C 2 H 5 -HSO 4
C 2 H 5 -HSO 4 Ethyl hydrogen sulphate + H 2 O steam ⟶ C 2 H 5 -OH Ethanol [ethyl alcohol] + H 2 SO 4 \underset{\text{ Ethyl hydrogen sulphate }}{\text{C}_2\text{H}_5\text{-HSO}_4} + \underset{\text{steam}}{\text{H}_2\text{O}} \longrightarrow \underset{ \text{ Ethanol [ethyl alcohol]} }{\text{C}_2\text{H}_5\text{-OH}} + \text{H}_2\text{SO}_4 Ethyl hydrogen sulphate C 2 H 5 -HSO 4 + steam H 2 O ⟶ Ethanol [ethyl alcohol] C 2 H 5 -OH + H 2 SO 4
(iv) By heating ethyl alcohol with concentrated H2 SO4 at 170°C.
C 2 H 5 OH ethyl alcohol → 170 ° C Conc. H 2 SO 4 [excess] C 2 H 4 ethene + H 2 O \underset{\text{ ethyl alcohol}}{\text{C}_2\text{H}_5\text{OH}} \xrightarrow[170\degree\text{C}]{\text{Conc. H}_2\text{SO}_4\text{[excess]}} \underset{ \text{ethene}}{\text{C}_2\text{H}_4} + \text{H}_2\text{O}\ ethyl alcohol C 2 H 5 OH Conc. H 2 SO 4 [excess] 170° C ethene C 2 H 4 + H 2 O