Solved 2024 Question Paper ICSE Class 10 Chemistry — Question 17

According to the given equation:

For N₂

4 vol. of NH₃ produce 2 vol. of N₂

∴ 240 cc of NH₃ will produce = $\dfrac{2 \times 240}{4}$ = 120 cc of N₂

For O₂

4 vol. of NH₃ reacts with 3 vol. of O₂

∴ 240 cc of NH₃ will react with = $\dfrac{3 \times 240}{4}$ = 180 cc of O₂.

Amount of unused Oxygen = 300 cc - 180 cc = 120 cc

Hence, composition of the resultant gaseous mixture at room temperature is 120 cc of O₂ + 120 cc of N₂