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ICSE Class 10 Chemistry Question 19 of 22

Solved 2024 Question Paper ICSE Class 10 Chemistry — Question 18

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18
Question

Question 7(iv)

The following table shows the electronic configuration of the atoms A, B, C and D.

ElementABCD
Electronic configuration2, 8, 8, 22, 62, 8, 72, 4

(a) Write the formula of the compound formed between:

  1. A and B
  2. D and C

(b) Which of the above elements will exhibit catenation?

Answer

(a)

  1. AB is the formula of the compound formed between A and B.
    Reason — A has 2 electrons in its outermost shell. B has 6 electrons in its outermost shell. To form a compound between A and B, A will donate its 2 outermost electrons to B. Hence, the formula of the compound is AB as both have 2 as valency.

  2. DC4 is the formula of the compound formed between D and C.
    Reason — D has 4 electrons in its outermost shell. C has 7 electrons in its outermost shell. Therefore, their valency is 4 and 1 respectively. So, 4 atoms of C will share their one electron each with one atom of D to form a compound. Hence, the formula of the compound is DC4.

(b) D will exhibit catenation.
Reason — Electronic configuration of D (2, 4) suggests that it is Carbon. Carbon exhibits catenation to the maximum extent due to tetra-covalency of carbon and greater strength of carbon-carbon bond.