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ICSE Class 10 Physics Question 4 of 20

Force — Question 6

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Question 6

The diagram shows two forces F1 = 5N and F2 = 3N acting at points A and B of a rod pivoted at a point O, such that OA = 2m and OB = 4m

Uniform metre rule balances horizontally on knife edge. Force, Concise Physics Class 10 Solutions.

Calculate:

(i) the moment of force F1 about O.

(ii) the moment of force F2 about O.

(iii) total moment of the two forces about O.

Answer

Given,

OA = 2m
OB = 4m
F1 = 5N
F2 = 3N

As we know,

Moment of force = F x r

Substituting the values of F and r

(i) Moment of force F1 about O

5×2=10Nm5 \times 2 = 10Nm

Therefore, moment of force F1 about O is 10Nm (anticlockwise)

(ii) Moment of force F2 about O

3×4=12Nm3 \times 4 = 12Nm

Therefore, moment of force F2 about O is 12Nm (clockwise)

(iii) Total moment of two forces about midpoint is

12−10=2Nm12 - 10 = 2Nm

Therefore, total moment of two forces about O is 2Nm (clockwise)