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ICSE Class 10 Physics Question 5 of 20

Force — Question 7

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Question 7

Two forces each of magnitude 10N act vertically upwards and downwards respectively at the two ends A and B of a uniform rod of length 4m which is pivoted at its mid-point O as shown. Determine the magnitude of resultant moment of forces about the pivot O.

Two forces each of magnitude 10N act vertically upwards and downwards respectively at the two ends A and B of a uniform rod of length 4m which is pivoted at its mid-point O as shown. Determine the magnitude of resultant moment of forces about the pivot O. Force, Concise Physics Class 10 Solutions.
Answer

Given,
Ab = 4m
OA = 2m
OB = 2m
Force at A = 10N
Force at B = 10N

As we know ,

Moment of force = F x r

Substituting the values of F and r

Moment of force about o at point A

10×2=20Nm clockwise10 \times 2 = 20Nm \text{ clockwise}

Moment of force about o at point B

10×2=20Nm clockwise10 \times 2 = 20Nm \text{ clockwise}

Total moment of forces about the centre O

20+20=40Nm20 + 20 = 40Nm \\[0.5em]

Total moment of force about the pivot O is 40 Nm (clockwise)