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ICSE Class 10 Physics Question 6 of 20

Force — Question 8

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Question 8

Figure shows two forces each of magnitude 10N acting at the points A and B at a separation of 50 cm, in opposite directions. Calculate the resultant moment of the two forces about the point (i) A, (ii) B and (iii) O, situated exactly at the middle of the two forces.

Figure shows two forces each of magnitude 10N acting at the points A and B at a separation of 50 cm, in opposite directions. Force, Concise Physics Class 10 Solutions.
Answer

Given,
Force at A = 10N
Force at B = 10N
Distance between A and B = 50cm = 0.5m

(i) Resultant moment of two forces at point A is

10×0.5=5Nm clockwise10 \times 0.5 = 5Nm \text{ clockwise} \\[0.5em]

Therefore, resultant moment of two forces at point A is 5 Nm (clockwise)

(ii) Resultant moment of two forces at point B is

10×0.5=5Nm clockwise10 \times 0.5 = 5Nm \text{ clockwise} \\[0.5em]

Therefore, resultant moment of two forces at point B is 5 Nm (clockwise)

(iii) Perpendicular distance of point O from either of the forces F = 10N is 0.25 m

Moment of force F at point A about O

10×0.25=2.5Nm clockwise10 \times 0.25 =2.5Nm \text{ clockwise} \\[0.5em]

Moment of force F at point B about O

10×0.25=2.5Nm clockwise10 \times 0.25 =2.5Nm \text{ clockwise} \\[0.5em]

Resultant moment of two forces about o is

2.5+2.5=5Nm clockwise2.5 + 2.5 = 5Nm \text{ clockwise} \\[0.5em]

Therefore, Resultant moment of two forces about o is 5Nm (clockwise)