Sound — Question 2

0.5 Hz

Reason — Given,

length = 1.0 m

g = 9.8 m/s²

We know,

frequency (f) = $\dfrac{1}{2π} \sqrt\dfrac{g}{L}$

Substituting we get,

frequency (f) = $\dfrac{1}{2π} \sqrt\dfrac{9.8}{1}$

frequency (f) = $\dfrac{1}{2π} \times 3.13$ = 0.49 ≈ 0.5 Hz