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ICSE Class 8 Physics Question 1 of 24

Force and Pressure — Question 2

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Question

Question 2

The moment of a force of 25 N about a point is 2.5 N m. Find the perpendicular distance of force from that point.

Answer

Given:
Force f = 25 N
Moment of force = 2.5 N m
Perpendicular distance d = ?

Moment of force=force (f)×distance (d)Distance (d)=Moment of forceForce (f)=2.525=0.1 m\text{Moment of force} = \text{force (f}) \times \text{distance (d)} \\[1em] \text{Distance (d)}= \dfrac{\text{Moment of force}}{\text{Force (f)}} \\[1em] = \dfrac{\text{2.5}}{\text{25}} \\[1em] = 0.1 \text{ m}

So, perpendicular distance of force from the point = 0.1 m or 10 cm.