Force and Pressure — Question 4

Given:
Moment of force = 2.0 N m
Diameter = 2 m
Radius = 1 m
Therefore perpendicular distance (d) = radius = 1 m
Force (f) = ?

$\text{Moment of force} = \text{force (f)} \times \text{distance (d)} \\[1em] \text{Force (f)}= \dfrac{\text{Moment of force}}{\text{distance (d)}} \\[1em] = \dfrac{\text{2.0}}{\text{1}} \\[1em] = 2 \text{ N}$

So, minimum force required is 2 N.