Current Electricity — Question 1

Given,

charge (q) = 1.5 C

work = 9 J

potential difference across the wire

$\text V = \dfrac{\text W}{\text q}$

Substituting the values in the formula, we get,

$\text V = \dfrac{9}{1.5} \\[0.5em] \Rightarrow \text V = 6\ \text V$

Hence, the potential difference across the wire = 6 V.