ICSE Class 9 Physics Question 6 of 19

Propagation of Sound Waves — Question 1

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Question 1

The heart of a man beats 75 times a minute. What is it's (a) frequency and (b) time period?

Answer

(a) Given,

Heart beats 75 times a minute

Converting minute into seconds, we get,

1 min = 60 s

As, frequency (f) is the number of times the heart beats in a second

Therefore, we get,

f=7560f=1.25 s1\text f = \dfrac{75}{60} \\[0.5em] \text f = 1.25 \text{ s}^{-1}

Hence, Frequency = 1.25 s-1

(b) Time period t = 1f\dfrac{1}{\text f}

Substituting the values, we get,

t=11.25t=0.8 s\text t = \dfrac{1}{1.25} \\[0.5em] \text t = 0.8\ s

Hence, t = 0.8 s