The time period of a simple pendulum is 2 s. Find it's frequency.
Given,
time (t) = 2 s
frequency = ?
As,
Frequency (f) = 1t\dfrac{1}{\text t}t1
Substituting the values, we get,
f=12f=0.5 Hz\text f = \dfrac{1}{2} \\[0.5em] \text f = 0.5 \text{ Hz}f=21f=0.5 Hz
Hence, f = 0.5 Hz