Propagation of Sound Waves — Question 8

Given,

Time (t)= 2.5 s

Speed of sound (V) = 340 m s^-1

Distance (d) = ?

V = $\dfrac{\text{Distance (d)}}{\text {Time (t)}}$

Substituting the values, we get,

$340 = \dfrac{\text d}{2.5} \\[0.5em] \Rightarrow \text d = 340 \times 2.5 \\[0.5em] \Rightarrow \text d = 850 \text { m} \\[0.5em]$

Therefore, the distance between the boys = 850 m.