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ICSE Class 9 Physics Question 13 of 19

Propagation of Sound Waves — Question 9

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Question

Question 9

An observer sitting in line of two tanks, watches the flashes of two tanks firing at each other at the same time, but he hears the sounds of two shots 2s and 3.5s after seeing the flashes. If distance between the two tanks is 510 m, find the speed of sound.

Answer

Given,

Time taken to hear the sound of tank 1 = 2 s

Time taken to hear the sound of tank 2 = 3.5 s

Time interval = 3.5 – 2 = 1.5 s

Distance between two tanks = 510 m

Velocity (V) = ?

V = Distance (d)Time (t)\dfrac{\text{Distance (d)}}{\text {Time (t)}}

Substituting the values, we get,

V=5101.5⇒V=340 m s−1\text V = \dfrac{510}{1.5} \\[0.5em] \Rightarrow \text V = 340 \text { m s}^{-1}\\[0.5em]

Therefore, the speed of sound = 340 m s-1 .