Question 1

Question 1Look at the activities listed below. Reason out whether or not work is done in the light of your understanding of the term 'work'.(a) Suma is swimming in a pond.(b) A donkey is carrying a load on its back.(c) A wind-mill is lifting water from a well.(d) A green plant is carrying out photosynthesis.(e) An engine is pulling a train.(f) Food grains are getting dried in the sun.(g) A sailboat is moving due to wind energy.

Accepted Answer

Work is said to be done when force applied on an object shows the displacement in that object.(a) While swimming, Suma applies a force to push the water backwards. She swims in the forward direction caused by the forward reaction of water. Here, the force causes a displacement. Hence, the work is done.(b) While carrying a load, the donkey has to apply a force in the upward direction. But, displacement of the load is in the forward direction. Since displacement is perpendicular to force, the work done is zero.(c) A windmill works against gravity to elevate water. The windmill lift water by applying a force in an upward direction, and thus the water is moving in the same upward direction itself. Hence, work is done.(d) No force is required when a green plant is carrying out photosynthesis and there is no displacement of plant. Hence, no work is done.(e) When an engine is pulling a train, it is applying a force in the forward direction and the train is moving. As, displacement and force are in the same direction. Hence, work is done.(f) As there is no force applied when grains are dried and there is no displacement as well. Hence, no work is done.(g) When a sailboat is moving due to wind energy, it is applying force in the forward direction. So, it is moving in the forward direction. As, displacement and force are in the same direction. Hence, work is done.

Question 2

Question 2An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

Accepted Answer

Given,Work done by gravity depends on the vertical displacement of the body.So, work done by gravity is :W = m g hwhere,Vertical displacement, h = 0 [∵ initial and the final points of the path of the object lie on the same horizontal line.]∴ W = m × g × 0 = 0Hence, work done by the force of gravity on the object = 0.

Question 3

Question 3A battery lights a bulb. Describe the energy changes involved in the process.

Accepted Answer

A battery converts chemical energy into electrical energy. When the bulb receives this electrical energy, it converts it into light and heat energy. Hence, energy changes involved in the process are :Chemical Energy ⟶ Electrical Energy ⟶ Light Energy + Heat Energy.

Question 4

Question 4Certain force acting on a 20 kg mass changes its velocity from 5 ms-1 to 2 ms-1. Calculate the work done by the force.

Accepted Answer

Given,Initial velocity u = 5 ms-1Mass of the body = 20 kgFinal velocity v = 2 ms-1Initial kinetic energyEi = 12\dfrac{1}{2}21​mu2Substituting we get,Ei = 12\dfrac{1}{2}21​ x 20 x 52= 10 × 25= 250 JFinal kinetic energyEf = 12\dfrac{1}{2}21​mv2= 12\dfrac{1}{2}21​ x 20 x 22= 10 × 4= 40 JAs, Work done = Change in kinetic energy = Ef – EiWork done = 40 J - 250 JWork done = -210 JHence, work done by the force = -210 J.

Question 5

Question 5A mass of 10 kg is at a point A on a table. It is moved to a point B. If the line joining A and B is horizontal, what is the work done on the object by the gravitational force? Explain your answer.

Accepted Answer

Given,Mass (m) = 10 kgWork done by gravity depends on the vertical displacement of the body. It is independent of the horizontal path.So, work done by gravity is = m g hWhere,Vertical displacement, h = 0 [∵ the line joining A and B is horizontal. ]∴ W = m × g × 0 = 0Hence, work done on object by gravity is zero.

Question 6

Question 6The potential energy of a freely falling object decreases progressively. Does this violate the law of conservation of energy? Why?

Accepted Answer

No. When the body falls from a height, its potential energy changes into kinetic energy progressively. A decrease in the potential energy is equal to an increase in the kinetic energy of the body. Hence, throughout the process, the total mechanical energy of the body remains conserved.Hence, the law of conservation of energy is not violated.

Question 7

Question 7What are the various energy transformations that occur when you are riding a bicycle?

Accepted Answer

The rider's muscular energy is converted to heat energy and the bicycle's kinetic energy while riding a bicycle. Hence, energy transformations are :Muscular energy ⟶ Kinetic energy + Heat energy

Question 8

Question 8Does the transfer of energy take place when you push a huge rock with all your might and fail to move it? Where is the energy you spend going?

Accepted Answer

When we push a huge rock and fail to move it, our muscular energy is not transferred to the rock as kinetic energy as there is no displacement of the rock. However, as per the law of conservation of energy, our muscular energy is transformed into heat energy that heats up our body and makes us sweat.

Question 9

Question 9A certain household has consumed 250 units of energy during a month. How much energy is this in joules?

Accepted Answer

Given,Energy (E) = 250 units1 kWh = 3.6 x 106 J1 unit of energy = 1 kWhSo, 250 units of energy = 250 × 3.6 × 106 = 9 × 108 J.Hence, 250 units of energy = 9 × 108 J.

Question 10

Question 10An object of mass 40 kg is raised to a height of 5 m above the ground. What is its potential energy? If the object is allowed to fall, find its kinetic energy when it is half-way down.

Accepted Answer

Given,Mass (m) = 40 kgAcceleration due to gravity = 10 ms-2Height (h) = 5 mPotential energy = ?We know,Potential energy = m g hSubstituting we get,P.E. = 40 × 10 × 5 = 2000 JHeight when halfway down : = 52\dfrac{5}{2}25​ = 2.5 mPotential energy when halfway = ?Substituting we get,P.E. = 40 × 10 × 2.5 = 1000 JAccording to the law of conservation of energy:Total potential energy = potential energy halfway down + kinetic energy halfway down2000 = 1000 + K.E. halfway downK.E. at halfway down = 2000 - 1000 = 1000 JHence, Potential energy = 2000 J and kinetic energy at halfway down = 1000 joules.

Question 11

Question 11What is the work done by the force of gravity on a satellite moving round the earth? Justify your answer.

Accepted Answer

When a satellite revolves around the earth in a circular orbit the work done is zero as force of gravity acting on satellite is perpendicular to its displacement.

Question 12

Question 12Can there be displacement of an object in the absence of any force acting on it? Think. Discuss this question with your friends and teacher

Accepted Answer

Yes, a uniformly moving object can experience displacement even when no force is acting on it. According to Newton's first law of motion, an object in motion will continue in its straight-line motion unless acted upon by an external force. Therefore, displacement of an object can occur in the absence of any force acting on it.

Question 13

Question 13A person holds a bundle of hay over his head for 30 minutes and gets tired. Has he done some work or not? Justify your answer.

Accepted Answer

Work is said to be done when force applied on an object shows the displacement in that object. In this case, as there is no displacement of the hay bundle, hence no work is done.

Question 14

Question 14An electric heater is rated 1500 W. How much energy does it use in 10 hours?

Accepted Answer

Given,Power of the heater = 1500 WConverting W to kW1000 W = 1 kWSo, 1500 W = 15001000\dfrac{1500}{1000}10001500​ = 1.5 kWTime taken = 10 hWe know,Power = Energy consumedTime taken\dfrac{	ext{Energy consumed}}{	ext{Time taken}}Time takenEnergy consumed​OrEnergy consumed = Power x Time takenSubstituting we get,Energy consumed = 1.5 x 10 = 15 kWhConverting kWh to J1 kWh = 3.6 x 106 JSo, 15 kWh = 3.6 x 106 x 15 = 5.4 x 107 JHence, the energy consumed = 5.4 x 107 J

Question 15

Question 15Illustrate the law of conservation of energy by discussing the energy changes which occur when we draw a pendulum bob to one side and allow it to oscillate. Why does the bob eventually come to rest? What happens to its energy eventually? Is it a violation of the law of conservation of energy?

Accepted Answer

The law of conservation of energy states that energy can only be converted from one form to another; it can neither be created or destroyed. The total energy before and after the transformation remains the same.Refer the figure of an oscillating pendulum bob shown below:The kinetic energy decreases and the potential energy becomes maximum at B.After a moment the the to and fro movement starts again.So, from B to A, again the potential energy changes into kinetic energy and this process repeats again and again.So, when the bob is in its state of to and fro movement it has potential energy at the extreme position B or C and kinetic energy at resting position A.It has both the kinetic energy and potential energy at an intermediate position. However, the sum of kinetic and potential energy remain same at every point of movement.The bob will eventually come to rest due to the frictional resistance offered by air on the surface of bob and pendulum loses its kinetic energy to overcome this friction and finally comes to rest.The law of conservation of energy is not violated because the kinetic energy lost by the pendulum to overcome the friction is gained by surroundings. Hence, total energy of the system will remain conserved.

Question 16

Question 16An object of mass, m is moving with a constant velocity, v. How much work should be done on the object in order to bring the object to rest?

Accepted Answer

The kinetic energy of an object of mass m, moving with a velocity, v, is given by the expression,Kinetic energy = 12\dfrac{1}{2}21​mv2In order to bring it to rest, its velocity has to be reduced to zero.An external force has to absorb energy from the object, i.e., do negative work on it, equal to its kinetic energy = −12-\dfrac{1}{2}−21​mv2

Question 17

Question 17Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 kmh-1.

Accepted Answer

Given,Mass (m) = 1500 kgInitial velocity (v) = 60 kmh-1Final velocity = 0Converting kmh-1 to ms-1 : multiply by 518\dfrac{5}{18}185​60 x 518\dfrac{5}{18}185​ = 503\dfrac{50}{3}350​ ms-1Work required to stop the moving car = Kinetic energy of car (K.E.)K.E. = 12\dfrac{1}{2}21​mv2= 12\dfrac{1}{2}21​ x 1500 x (503)(\dfrac{50}{3})(350​)2= 12\dfrac{1}{2}21​ x 1500 x 25009\dfrac{2500}{9}92500​= 208333.3 JHence, work done = 208333.3 J.

Question 18

Question 18In each of the following a force, F is acting on an object of mass, m. The direction of displacement is from west to east shown by the longer arrow. Observe the diagrams carefully and state whether the work done by the force is negative, positive or zero.

Accepted Answer

Case IThe direction of force acting on the block is perpendicular to the displacement. Hence, work done by force on the block will be zero.Case IIThe direction of force acting on the block is in the direction of displacement. Hence, work done by force on the block will be positive.Case IIIThe direction of force acting on the block is opposite to the direction of displacement. Hence, work done by force on the block will be negative.

Question 19

Question 19Soni says that the acceleration in an object could be zero even when several forces are acting on it. Do you agree with her? Why?

Accepted Answer

Acceleration in an object could be zero even when several forces are acting on it. This happens when all the forces cancel out each other i.e., the net force acting on the object is zero.Consider the below object:F = maF = 0 [∵ equal and opposite forces cancel out each other]∴ 0 = ma⇒ a = 0∴ Vfinal = VinitialHence, if the object was initially moving, it will continue to move with uniform velocity without acceleration.Therefore, I agree with Soni's statement.

Question 20

Question 20Find the energy in joules consumed in 10 hours by four devices of power 500 W each.

Accepted Answer

Given,Power rating (P) = 500 WConverting W into kW1000 W = 1 kW500 W = 5001000\dfrac{500}{1000}1000500​ = 0.5 kWTime (T) = 10 hWe know,Power = Energy consumedTime taken\dfrac{	ext{Energy consumed}}{	ext{Time taken}}Time takenEnergy consumed​OrEnergy consumed by each device = Power x Time takenSubstituting we get,Energy consumed by each device = 0.5 x 10 = 5 kWhEnergy consumed by four devices = 4 x 5 = 20 kWhConverting kWh to J1 kWh = 3.6 x 106 JSo, 20 kWh = 3.6 x 106 x 20 = 7.2 x 107 JHence, the energy consumed = 7.2 x 107 J

Work and Energy

Exercises

Intext Questions 1

Intext Questions 2

Intext Questions 3

Intext Questions 5